Base | Representation |
---|---|
bin | 10000011110100010011… |
… | …011001011001100110011 |
3 | 11000020200000220111202101 |
4 | 100132202123023030303 |
5 | 122022423131302403 |
6 | 2224101101201231 |
7 | 144543325236346 |
oct | 20364233131463 |
9 | 4006600814671 |
10 | 1132301431603 |
11 | 3a722a703711 |
12 | 163545560217 |
13 | 82a10bc7004 |
14 | 3cb3743445d |
15 | 1e6c168071d |
hex | 107a26cb333 |
1132301431603 has 2 divisors, whose sum is σ = 1132301431604. Its totient is φ = 1132301431602.
The previous prime is 1132301431601. The next prime is 1132301431631. The reversal of 1132301431603 is 3061341032311.
It is an a-pointer prime, because the next prime (1132301431631) can be obtained adding 1132301431603 to its sum of digits (28).
It is a weak prime.
It is an emirp because it is prime and its reverse (3061341032311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1132301431603 - 21 = 1132301431601 is a prime.
Together with 1132301431601, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1132301431601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566150715801 + 566150715802.
It is an arithmetic number, because the mean of its divisors is an integer number (566150715802).
Almost surely, 21132301431603 is an apocalyptic number.
1132301431603 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132301431603 is an equidigital number, since it uses as much as digits as its factorization.
1132301431603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 1132301431603 its reverse (3061341032311), we get a palindrome (4193642463914).
The spelling of 1132301431603 in words is "one trillion, one hundred thirty-two billion, three hundred one million, four hundred thirty-one thousand, six hundred three".
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