Base | Representation |
---|---|
bin | 110100101110100011… |
… | …0011010101111011111 |
3 | 101211021021022112101201 |
4 | 1221131012122233133 |
5 | 3323344131110213 |
6 | 124003451420331 |
7 | 11115654403336 |
oct | 1513506325737 |
9 | 354237275351 |
10 | 113231113183 |
11 | 44026014291 |
12 | 19b40a546a7 |
13 | a8a6a402b6 |
14 | 56a238ad1d |
15 | 2e2aade6dd |
hex | 1a5d19abdf |
113231113183 has 2 divisors, whose sum is σ = 113231113184. Its totient is φ = 113231113182.
The previous prime is 113231113133. The next prime is 113231113213. The reversal of 113231113183 is 381311132311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113231113183 - 233 = 104641178591 is a prime.
It is a super-2 number, since 2×1132311131832 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113231113133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615556591 + 56615556592.
It is an arithmetic number, because the mean of its divisors is an integer number (56615556592).
Almost surely, 2113231113183 is an apocalyptic number.
113231113183 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231113183 is an equidigital number, since it uses as much as digits as its factorization.
113231113183 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 28.
Adding to 113231113183 its reverse (381311132311), we get a palindrome (494542245494).
The spelling of 113231113183 in words is "one hundred thirteen billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred eighty-three".
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