Base | Representation |
---|---|
bin | 1010010011000101111100… |
… | …1010010100100001110111 |
3 | 1111002110222102101101022202 |
4 | 2210301133022110201313 |
5 | 2441004232331131203 |
6 | 40025435124015115 |
7 | 2246032503535025 |
oct | 244613712244167 |
9 | 44073872341282 |
10 | 11323130333303 |
11 | 3676126974a48 |
12 | 132a5b953149b |
13 | 6419c73161c9 |
14 | 2b2084611715 |
15 | 149819820388 |
hex | a4c5f294877 |
11323130333303 has 2 divisors, whose sum is σ = 11323130333304. Its totient is φ = 11323130333302.
The previous prime is 11323130333297. The next prime is 11323130333341. The reversal of 11323130333303 is 30333303132311.
It is a happy number.
11323130333303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11323130333303 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323130333503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661565166651 + 5661565166652.
It is an arithmetic number, because the mean of its divisors is an integer number (5661565166652).
Almost surely, 211323130333303 is an apocalyptic number.
11323130333303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323130333303 is an equidigital number, since it uses as much as digits as its factorization.
11323130333303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 29.
Adding to 11323130333303 its reverse (30333303132311), we get a palindrome (41656433465614).
The spelling of 11323130333303 in words is "eleven trillion, three hundred twenty-three billion, one hundred thirty million, three hundred thirty-three thousand, three hundred three".
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