11323361255147 has 2 divisors, whose sum is σ = 11323361255148. Its totient is φ = 11323361255146.

The previous prime is 11323361255099. The next prime is 11323361255149. The reversal of 11323361255147 is 74155216332311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11323361255147 - 2¹⁰ = 11323361254123 is a prime.

It is a super-2 number, since 2×11323361255147² (a number of 27 digits) contains 22 as substring.

Together with 11323361255149, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11323361255098 and 11323361255107.

It is not a weakly prime, because it can be changed into another prime (11323361255149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661680627573 + 5661680627574.

It is an arithmetic number, because the mean of its divisors is an integer number (5661680627574).

Almost surely, 2^{11323361255147} is an apocalyptic number.

11323361255147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323361255147 is an equidigital number, since it uses as much as digits as its factorization.

11323361255147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 453600, while the sum is 44.

Adding to 11323361255147 its reverse (74155216332311), we get a palindrome (85478577587458).

The spelling of 11323361255147 in words is "eleven trillion, three hundred twenty-three billion, three hundred sixty-one million, two hundred fifty-five thousand, one hundred forty-seven".