1132401201431 has 2 divisors, whose sum is σ = 1132401201432. Its totient is φ = 1132401201430.

The previous prime is 1132401201331. The next prime is 1132401201469. The reversal of 1132401201431 is 1341021042311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1132401201431 - 2¹⁰ = 1132401200407 is a prime.

It is a super-2 number, since 2×1132401201431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1132401201397 and 1132401201406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1132401201331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566200600715 + 566200600716.

It is an arithmetic number, because the mean of its divisors is an integer number (566200600716).

Almost surely, 2^{1132401201431} is an apocalyptic number.

1132401201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132401201431 is an equidigital number, since it uses as much as digits as its factorization.

1132401201431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1132401201431 its reverse (1341021042311), we get a palindrome (2473422243742).

The spelling of 1132401201431 in words is "one trillion, one hundred thirty-two billion, four hundred one million, two hundred one thousand, four hundred thirty-one".