Base | Representation |
---|---|
bin | 10000011110101000011… |
… | …000001001111101000111 |
3 | 11000020220222211112001121 |
4 | 100132220120021331013 |
5 | 122023124213201432 |
6 | 2224115025534411 |
7 | 144545650155565 |
oct | 20365030117507 |
9 | 4006828745047 |
10 | 1132401303367 |
11 | 3a7281017864 |
12 | 163572aa4407 |
13 | 82a287c4329 |
14 | 3cb467d0a35 |
15 | 1e6ca30c197 |
hex | 107a8609f47 |
1132401303367 has 2 divisors, whose sum is σ = 1132401303368. Its totient is φ = 1132401303366.
The previous prime is 1132401303359. The next prime is 1132401303401. The reversal of 1132401303367 is 7633031042311.
It is an a-pointer prime, because the next prime (1132401303401) can be obtained adding 1132401303367 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1132401303367 - 23 = 1132401303359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132401303337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566200651683 + 566200651684.
It is an arithmetic number, because the mean of its divisors is an integer number (566200651684).
Almost surely, 21132401303367 is an apocalyptic number.
1132401303367 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132401303367 is an equidigital number, since it uses as much as digits as its factorization.
1132401303367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 34.
Adding to 1132401303367 its reverse (7633031042311), we get a palindrome (8765432345678).
The spelling of 1132401303367 in words is "one trillion, one hundred thirty-two billion, four hundred one million, three hundred three thousand, three hundred sixty-seven".
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