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113241203300355 = 3513580724119489
BaseRepresentation
bin11001101111111000000101…
…101100100101100000000011
3112211221202100011101021022220
4121233320011230211200003
5104320320441021102410
61040502142435102123
732565256404144024
oct3157700554454003
9484852304337286
10113241203300355
113309a363086509
121084aaa1a41943
134b257a4581510
141dd6c91234c4b
15d159e4851070
hex66fe05b25803

113241203300355 has 16 divisors (see below), whose sum is σ = 195123304148640. Its totient is φ = 55749515470848.

The previous prime is 113241203300339. The next prime is 113241203300479. The reversal of 113241203300355 is 553003302142311.

It is not a de Polignac number, because 113241203300355 - 24 = 113241203300339 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290362059550 + ... + 290362059939.

It is an arithmetic number, because the mean of its divisors is an integer number (12195206509290).

Almost surely, 2113241203300355 is an apocalyptic number.

113241203300355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

113241203300355 is a deficient number, since it is larger than the sum of its proper divisors (81882100848285).

113241203300355 is a wasteful number, since it uses less digits than its factorization.

113241203300355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 580724119510.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 113241203300355 its reverse (553003302142311), we get a palindrome (666244505442666).

The spelling of 113241203300355 in words is "one hundred thirteen trillion, two hundred forty-one billion, two hundred three million, three hundred thousand, three hundred fifty-five".

Divisors: 1 3 5 13 15 39 65 195 580724119489 1742172358467 2903620597445 7549413553357 8710861792335 22648240660071 37747067766785 113241203300355