11324141433 has 24 divisors (see below), whose sum is σ = 18002031840. Its totient is φ = 6802373760.

The previous prime is 11324141419. The next prime is 11324141453. The reversal of 11324141433 is 33414142311.

11324141433 is a `hidden beast` number, since 1 + 1 + 3 + 241 + 414 + 3 + 3 = 666.

It is not a de Polignac number, because 11324141433 - 2⁸ = 11324141177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11324141397 and 11324141406.

It is not an unprimeable number, because it can be changed into a prime (11324141453) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 494943 + ... + 517316.

It is an arithmetic number, because the mean of its divisors is an integer number (750084660).

Almost surely, 2^11324141433 is an apocalyptic number.

It is an amenable number.

11324141433 is a deficient number, since it is larger than the sum of its proper divisors (6677890407).

11324141433 is a wasteful number, since it uses less digits than its factorization.

11324141433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1012389 (or 1012386 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 11324141433 its reverse (33414142311), we get a palindrome (44738283744).

The spelling of 11324141433 in words is "eleven billion, three hundred twenty-four million, one hundred forty-one thousand, four hundred thirty-three".