Search a number
-
+
11324213151100 = 2252113242131511
BaseRepresentation
bin1010010011001001111110…
…1100111100010101111100
31111002120202212220020002121
42210302133230330111330
52441013442031313400
640030134404332324
72246101362406153
oct244623754742574
944076685806077
1011324213151100
113676632113a93
12132a8600a40a4
13641b3a75c1b5
142b214835a59a
1514987e91021a
hexa4c9fb3c57c

11324213151100 has 18 divisors (see below), whose sum is σ = 24573542538104. Its totient is φ = 4529685260400.

The previous prime is 11324213151091. The next prime is 11324213151133. The reversal of 11324213151100 is 115131242311.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56621065656 + ... + 56621065855.

Almost surely, 211324213151100 is an apocalyptic number.

11324213151100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11324213151100 is an abundant number, since it is smaller than the sum of its proper divisors (13249329387004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11324213151100 is a wasteful number, since it uses less digits than its factorization.

11324213151100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113242131525 (or 113242131518 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 11324213151100 its reverse (115131242311), we get a palindrome (11439344393411).

The spelling of 11324213151100 in words is "eleven trillion, three hundred twenty-four billion, two hundred thirteen million, one hundred fifty-one thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 113242131511 226484263022 452968526044 566210657555 1132421315110 2264842630220 2831053287775 5662106575550 11324213151100