Base | Representation |
---|---|
bin | 1010010011001001111110… |
… | …1100111100010101111100 |
3 | 1111002120202212220020002121 |
4 | 2210302133230330111330 |
5 | 2441013442031313400 |
6 | 40030134404332324 |
7 | 2246101362406153 |
oct | 244623754742574 |
9 | 44076685806077 |
10 | 11324213151100 |
11 | 3676632113a93 |
12 | 132a8600a40a4 |
13 | 641b3a75c1b5 |
14 | 2b214835a59a |
15 | 14987e91021a |
hex | a4c9fb3c57c |
11324213151100 has 18 divisors (see below), whose sum is σ = 24573542538104. Its totient is φ = 4529685260400.
The previous prime is 11324213151091. The next prime is 11324213151133. The reversal of 11324213151100 is 115131242311.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56621065656 + ... + 56621065855.
Almost surely, 211324213151100 is an apocalyptic number.
11324213151100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11324213151100 is an abundant number, since it is smaller than the sum of its proper divisors (13249329387004).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11324213151100 is a wasteful number, since it uses less digits than its factorization.
11324213151100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113242131525 (or 113242131518 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 11324213151100 its reverse (115131242311), we get a palindrome (11439344393411).
The spelling of 11324213151100 in words is "eleven trillion, three hundred twenty-four billion, two hundred thirteen million, one hundred fifty-one thousand, one hundred".
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