Base | Representation |
---|---|
bin | 110100101110111011… |
… | …1101101000001011000 |
3 | 101211022011121221012121 |
4 | 1221131313231001120 |
5 | 3323410433024422 |
6 | 124005032351024 |
7 | 11116202253640 |
oct | 1513567550130 |
9 | 354264557177 |
10 | 113244033112 |
11 | 44032339211 |
12 | 19b45245474 |
13 | a8a9614c22 |
14 | 56a3d91520 |
15 | 2e2bce28c7 |
hex | 1a5dded058 |
113244033112 has 16 divisors (see below), whose sum is σ = 242665785360. Its totient is φ = 48533157024.
The previous prime is 113244033101. The next prime is 113244033113. The reversal of 113244033112 is 211330442311.
It is a super-2 number, since 2×1132440331122 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113244033113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1011107383 + ... + 1011107494.
It is an arithmetic number, because the mean of its divisors is an integer number (15166611585).
Almost surely, 2113244033112 is an apocalyptic number.
It is an amenable number.
113244033112 is an abundant number, since it is smaller than the sum of its proper divisors (129421752248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113244033112 is a wasteful number, since it uses less digits than its factorization.
113244033112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2022214890 (or 2022214886 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 113244033112 its reverse (211330442311), we get a palindrome (324574475423).
The spelling of 113244033112 in words is "one hundred thirteen billion, two hundred forty-four million, thirty-three thousand, one hundred twelve".
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