Base | Representation |
---|---|
bin | 11001101111111011000100… |
… | …010100000110110000101001 |
3 | 112211222001121001001001222021 |
4 | 121233323010110012300221 |
5 | 104320344013220044431 |
6 | 1040503432040024441 |
7 | 32565431556023155 |
oct | 3157730424066051 |
9 | 484861531031867 |
10 | 113244401331241 |
11 | 330a0754304444 |
12 | 1084b634a62121 |
13 | 4b25b93cb099b |
14 | 1dd70b5c6a065 |
15 | d15b304b0b11 |
hex | 66fec4506c29 |
113244401331241 has 8 divisors (see below), whose sum is σ = 113521813493760. Its totient is φ = 112966991759712.
The previous prime is 113244401331151. The next prime is 113244401331253. The reversal of 113244401331241 is 142133104442311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113244401331241 is a prime.
It is a super-4 number, since 4×1132444013312414 (a number of 57 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113244401331197 and 113244401331206.
It is not an unprimeable number, because it can be changed into a prime (113244401331041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109976016 + ... + 111000958.
It is an arithmetic number, because the mean of its divisors is an integer number (14190226686720).
Almost surely, 2113244401331241 is an apocalyptic number.
It is an amenable number.
113244401331241 is a deficient number, since it is larger than the sum of its proper divisors (277412162519).
113244401331241 is a wasteful number, since it uses less digits than its factorization.
113244401331241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1295495.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 113244401331241 its reverse (142133104442311), we get a palindrome (255377505773552).
The spelling of 113244401331241 in words is "one hundred thirteen trillion, two hundred forty-four billion, four hundred one million, three hundred thirty-one thousand, two hundred forty-one".
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