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113246505313 is a prime number
BaseRepresentation
bin110100101111000000…
…1001000100101100001
3101211022100021112102121
41221132001020211201
53323412101132223
6124005201344241
711116232261344
oct1513601104541
9354270245377
10113246505313
1144033777657
1219b46038081
13a8a9c9c276
1456a443645b
152e2c13015d
hex1a5e048961

113246505313 has 2 divisors, whose sum is σ = 113246505314. Its totient is φ = 113246505312.

The previous prime is 113246505259. The next prime is 113246505347. The reversal of 113246505313 is 313505642311.

It is an a-pointer prime, because the next prime (113246505347) can be obtained adding 113246505313 to its sum of digits (34).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100430680464 + 12815824849 = 316908^2 + 113207^2 .

It is an emirp because it is prime and its reverse (313505642311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113246505313 - 225 = 113212950881 is a prime.

It is not a weakly prime, because it can be changed into another prime (113246505913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56623252656 + 56623252657.

It is an arithmetic number, because the mean of its divisors is an integer number (56623252657).

Almost surely, 2113246505313 is an apocalyptic number.

It is an amenable number.

113246505313 is a deficient number, since it is larger than the sum of its proper divisors (1).

113246505313 is an equidigital number, since it uses as much as digits as its factorization.

113246505313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

The spelling of 113246505313 in words is "one hundred thirteen billion, two hundred forty-six million, five hundred five thousand, three hundred thirteen".