Base | Representation |
---|---|
bin | 110100101111000000… |
… | …1001000101110111001 |
3 | 101211022100021120020211 |
4 | 1221132001020232321 |
5 | 3323412101142123 |
6 | 124005201351121 |
7 | 11116232263162 |
oct | 1513601105671 |
9 | 354270246224 |
10 | 113246505913 |
11 | 44033778052 |
12 | 19b460384a1 |
13 | a8a9c9c618 |
14 | 56a4436769 |
15 | 2e2c13040d |
hex | 1a5e048bb9 |
113246505913 has 2 divisors, whose sum is σ = 113246505914. Its totient is φ = 113246505912.
The previous prime is 113246505901. The next prime is 113246505937. The reversal of 113246505913 is 319505642311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60719366569 + 52527139344 = 246413^2 + 229188^2 .
It is a cyclic number.
It is not a de Polignac number, because 113246505913 - 217 = 113246374841 is a prime.
It is a super-2 number, since 2×1132465059132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113246505313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56623252956 + 56623252957.
It is an arithmetic number, because the mean of its divisors is an integer number (56623252957).
Almost surely, 2113246505913 is an apocalyptic number.
It is an amenable number.
113246505913 is a deficient number, since it is larger than the sum of its proper divisors (1).
113246505913 is an equidigital number, since it uses as much as digits as its factorization.
113246505913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 113246505913 in words is "one hundred thirteen billion, two hundred forty-six million, five hundred five thousand, nine hundred thirteen".
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