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1132514325245 = 5593839031611
BaseRepresentation
bin10000011110101111000…
…111010011001011111101
311000021012212111121221002
4100132233013103023331
5122023342131401440
62224134144220045
7144551521634462
oct20365707231375
94007185447832
101132514325245
113a73298a2876
121635a490a625
1382a46046c94
143cb57811669
151e6d51d5115
hex107af1d32fd

1132514325245 has 8 divisors (see below), whose sum is σ = 1382051380320. Its totient is φ = 890655333520.

The previous prime is 1132514325211. The next prime is 1132514325253. The reversal of 1132514325245 is 5425234152311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1132514325245 - 218 = 1132514063101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1132514325199 and 1132514325208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1919515511 + ... + 1919516100.

It is an arithmetic number, because the mean of its divisors is an integer number (172756422540).

Almost surely, 21132514325245 is an apocalyptic number.

It is an amenable number.

1132514325245 is a deficient number, since it is larger than the sum of its proper divisors (249537055075).

1132514325245 is an equidigital number, since it uses as much as digits as its factorization.

1132514325245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3839031675.

The product of its digits is 144000, while the sum is 38.

Adding to 1132514325245 its reverse (5425234152311), we get a palindrome (6557748477556).

The spelling of 1132514325245 in words is "one trillion, one hundred thirty-two billion, five hundred fourteen million, three hundred twenty-five thousand, two hundred forty-five".

Divisors: 1 5 59 295 3839031611 19195158055 226502865049 1132514325245