Base | Representation |
---|---|
bin | 110100101111001011… |
… | …1101100111100011111 |
3 | 101211022202102002210012 |
4 | 1221132113230330133 |
5 | 3323420104441112 |
6 | 124005532233435 |
7 | 11116333461416 |
oct | 1513627547437 |
9 | 354282362705 |
10 | 113252421407 |
11 | 44037048494 |
12 | 19b4800b87b |
13 | a8ab291008 |
14 | 56a513647d |
15 | 2e2c8ed022 |
hex | 1a5e5ecf1f |
113252421407 has 2 divisors, whose sum is σ = 113252421408. Its totient is φ = 113252421406.
The previous prime is 113252421379. The next prime is 113252421437. The reversal of 113252421407 is 704124252311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113252421407 - 26 = 113252421343 is a prime.
It is a super-2 number, since 2×1132524214072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113252421437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626210703 + 56626210704.
It is an arithmetic number, because the mean of its divisors is an integer number (56626210704).
Almost surely, 2113252421407 is an apocalyptic number.
113252421407 is a deficient number, since it is larger than the sum of its proper divisors (1).
113252421407 is an equidigital number, since it uses as much as digits as its factorization.
113252421407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 113252421407 its reverse (704124252311), we get a palindrome (817376673718).
The spelling of 113252421407 in words is "one hundred thirteen billion, two hundred fifty-two million, four hundred twenty-one thousand, four hundred seven".
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