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113252421445 = 579359798649
BaseRepresentation
bin110100101111001011…
…1101100111101000101
3101211022202102002211121
41221132113230331011
53323420104441240
6124005532233541
711116333461502
oct1513627547505
9354282362747
10113252421445
1144037048519
1219b4800b8b1
13a8ab291037
1456a51364a9
152e2c8ed04a
hex1a5e5ecf45

113252421445 has 16 divisors (see below), whose sum is σ = 138006720000. Its totient is φ = 89205787008.

The previous prime is 113252421437. The next prime is 113252421463. The reversal of 113252421445 is 544124252311.

It is a cyclic number.

It is not a de Polignac number, because 113252421445 - 23 = 113252421437 is a prime.

It is a super-2 number, since 2×1132524214452 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113252421445.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 257520 + ... + 541129.

It is an arithmetic number, because the mean of its divisors is an integer number (8625420000).

Almost surely, 2113252421445 is an apocalyptic number.

It is an amenable number.

113252421445 is a deficient number, since it is larger than the sum of its proper divisors (24754298555).

113252421445 is an equidigital number, since it uses as much as digits as its factorization.

113252421445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 799092.

The product of its digits is 38400, while the sum is 34.

Adding to 113252421445 its reverse (544124252311), we get a palindrome (657376673756).

The spelling of 113252421445 in words is "one hundred thirteen billion, two hundred fifty-two million, four hundred twenty-one thousand, four hundred forty-five".

Divisors: 1 5 79 359 395 1795 28361 141805 798649 3993245 63093271 286714991 315466355 1433574955 22650484289 113252421445