Base | Representation |
---|---|
bin | 110100101111001101… |
… | …0011111100101101111 |
3 | 101211022210210021112020 |
4 | 1221132122133211233 |
5 | 3323420301400020 |
6 | 124010000041223 |
7 | 11116342626633 |
oct | 1513632374557 |
9 | 354283707466 |
10 | 113253153135 |
11 | 440374a8221 |
12 | 19b48303213 |
13 | a8ab4890a5 |
14 | 56a5286dc3 |
15 | 2e2c9e4c40 |
hex | 1a5e69f96f |
113253153135 has 8 divisors (see below), whose sum is σ = 181205045040. Its totient is φ = 60401681664.
The previous prime is 113253153131. The next prime is 113253153217. The reversal of 113253153135 is 531351352311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113253153135 - 22 = 113253153131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113253153096 and 113253153105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113253153131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3775105090 + ... + 3775105119.
It is an arithmetic number, because the mean of its divisors is an integer number (22650630630).
Almost surely, 2113253153135 is an apocalyptic number.
113253153135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113253153135 is a deficient number, since it is larger than the sum of its proper divisors (67951891905).
113253153135 is an equidigital number, since it uses as much as digits as its factorization.
113253153135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7550210217.
The product of its digits is 20250, while the sum is 33.
The spelling of 113253153135 in words is "one hundred thirteen billion, two hundred fifty-three million, one hundred fifty-three thousand, one hundred thirty-five".
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