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11325355511 = 17666197383
BaseRepresentation
bin10101000110000101…
…10011010111110111
31002020021122200002112
422203002303113313
5141143242334021
65111445401235
7550436635121
oct124302632767
932207580075
1011325355511
114891960248
122240a0921b
1310b64623c2
147961a4211
1546440ad5b
hex2a30b35f7

11325355511 has 4 divisors (see below), whose sum is σ = 11991552912. Its totient is φ = 10659158112.

The previous prime is 11325355463. The next prime is 11325355513. The reversal of 11325355511 is 11555352311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11325355511 is a prime.

It is a super-3 number, since 3×113253555113 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11325355513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333098675 + ... + 333098708.

It is an arithmetic number, because the mean of its divisors is an integer number (2997888228).

Almost surely, 211325355511 is an apocalyptic number.

11325355511 is a deficient number, since it is larger than the sum of its proper divisors (666197401).

11325355511 is an equidigital number, since it uses as much as digits as its factorization.

11325355511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666197400.

The product of its digits is 11250, while the sum is 32.

The spelling of 11325355511 in words is "eleven billion, three hundred twenty-five million, three hundred fifty-five thousand, five hundred eleven".

Divisors: 1 17 666197383 11325355511