Base | Representation |
---|---|
bin | 11001110000000100000011… |
… | …011010111001011101111101 |
3 | 112211222222111110201210100001 |
4 | 121300010003122321131331 |
5 | 104321023243300323010 |
6 | 1040512105312434301 |
7 | 32566222636321651 |
oct | 3160040332713575 |
9 | 484888443653301 |
10 | 113254050011005 |
11 | 330a4855782352 |
12 | 10851488248991 |
13 | 4b26a70c72057 |
14 | 1dd774d49aa61 |
15 | d15ee75c3c3a |
hex | 6701036b977d |
113254050011005 has 64 divisors (see below), whose sum is σ = 145328858357760. Its totient is φ = 84575769255936.
The previous prime is 113254050010573. The next prime is 113254050011009. The reversal of 113254050011005 is 500110050452311.
It is a cyclic number.
It is not a de Polignac number, because 113254050011005 - 229 = 113253513140093 is a prime.
It is a super-2 number, since 2×1132540500110052 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113254050011009) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 342703729 + ... + 343034041.
It is an arithmetic number, because the mean of its divisors is an integer number (2270763411840).
Almost surely, 2113254050011005 is an apocalyptic number.
It is an amenable number.
113254050011005 is a deficient number, since it is larger than the sum of its proper divisors (32074808346755).
113254050011005 is a wasteful number, since it uses less digits than its factorization.
113254050011005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 330950.
The product of its (nonzero) digits is 3000, while the sum is 28.
The spelling of 113254050011005 in words is "one hundred thirteen trillion, two hundred fifty-four billion, fifty million, eleven thousand, five".
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