Base | Representation |
---|---|
bin | 1010010011001110100100… |
… | …0101110011011111100111 |
3 | 1111002200221200201102020011 |
4 | 2210303221011303133213 |
5 | 2441024002231431343 |
6 | 40030500510351051 |
7 | 2246144033035264 |
oct | 244635105633747 |
9 | 44080850642204 |
10 | 11325444405223 |
11 | 3677104127483 |
12 | 132ab444bb487 |
13 | 641ca5877430 |
14 | 2b2223aa426b |
15 | 149902a7129d |
hex | a4ce91737e7 |
11325444405223 has 32 divisors (see below), whose sum is σ = 12370179548160. Its totient is φ = 10306444406400.
The previous prime is 11325444405217. The next prime is 11325444405239. The reversal of 11325444405223 is 32250444452311.
It is a cyclic number.
It is not a de Polignac number, because 11325444405223 - 213 = 11325444397031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11325444405203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 528746208 + ... + 528767626.
It is an arithmetic number, because the mean of its divisors is an integer number (386568110880).
Almost surely, 211325444405223 is an apocalyptic number.
11325444405223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11325444405223 is a deficient number, since it is larger than the sum of its proper divisors (1044735142937).
11325444405223 is a wasteful number, since it uses less digits than its factorization.
11325444405223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23239.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 11325444405223 its reverse (32250444452311), we get a palindrome (43575888857534).
The spelling of 11325444405223 in words is "eleven trillion, three hundred twenty-five billion, four hundred forty-four million, four hundred five thousand, two hundred twenty-three".
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