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11328538330181 is a prime number
BaseRepresentation
bin1010010011011010000110…
…0000001100010001000101
31111002222221022111002101102
42210312201200030101011
52441101321303031211
640032131512105445
72246313512001542
oct244664140142105
944088838432342
1011328538330181
11367845160a056
12132b668695285
13642379856267
142b2438959bc9
15149a344b9a3b
hexa4da180c445

11328538330181 has 2 divisors, whose sum is σ = 11328538330182. Its totient is φ = 11328538330180.

The previous prime is 11328538330103. The next prime is 11328538330183. The reversal of 11328538330181 is 18103383582311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10103180102500 + 1225358227681 = 3178550^2 + 1106959^2 .

It is a cyclic number.

It is not a de Polignac number, because 11328538330181 - 218 = 11328538068037 is a prime.

It is a super-2 number, since 2×113285383301812 (a number of 27 digits) contains 22 as substring.

Together with 11328538330183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11328538330183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5664269165090 + 5664269165091.

It is an arithmetic number, because the mean of its divisors is an integer number (5664269165091).

Almost surely, 211328538330181 is an apocalyptic number.

It is an amenable number.

11328538330181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11328538330181 is an equidigital number, since it uses as much as digits as its factorization.

11328538330181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 47.

The spelling of 11328538330181 in words is "eleven trillion, three hundred twenty-eight billion, five hundred thirty-eight million, three hundred thirty thousand, one hundred eighty-one".