Base | Representation |
---|---|
bin | 1010010011011111100010… |
… | …1100010010101100001110 |
3 | 1111010010201020222111210122 |
4 | 2210313320230102230032 |
5 | 2441112320241320024 |
6 | 40032533004504542 |
7 | 2246364663341123 |
oct | 244677054225416 |
9 | 44103636874718 |
10 | 11330001120014 |
11 | 3679032294775 |
12 | 132b9b654b152 |
13 | 64255091a785 |
14 | 2b2536d3474a |
15 | 149abcb13d5e |
hex | a4df8b12b0e |
11330001120014 has 16 divisors (see below), whose sum is σ = 17316037271520. Its totient is φ = 5557993328160.
The previous prime is 11330001120013. The next prime is 11330001120029. The reversal of 11330001120014 is 41002110003311.
11330001120014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11330001119974 and 11330001120001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11330001120013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3859352 + ... + 6128180.
It is an arithmetic number, because the mean of its divisors is an integer number (1082252329470).
Almost surely, 211330001120014 is an apocalyptic number.
11330001120014 is a deficient number, since it is larger than the sum of its proper divisors (5986036151506).
11330001120014 is a wasteful number, since it uses less digits than its factorization.
11330001120014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2315995.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11330001120014 its reverse (41002110003311), we get a palindrome (52332111123325).
The spelling of 11330001120014 in words is "eleven trillion, three hundred thirty billion, one million, one hundred twenty thousand, fourteen".
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