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11330004400 = 2452113131637
BaseRepresentation
bin10101000110101001…
…00010010110110000
31002020121101212011121
422203110202112300
5141200440120100
65112133152024
7550524306541
oct124324422660
932217355147
1011330004400
114894546000
12224248b614
1310b73cc420
14796a544c8
15464a2851a
hex2a35225b0

11330004400 has 240 divisors, whose sum is σ = 32263122528. Its totient is φ = 3800755200.

The previous prime is 11330004349. The next prime is 11330004451. The reversal of 11330004400 is 440003311.

It is an interprime number because it is at equal distance from previous prime (11330004349) and next prime (11330004451).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a zygodrome in base 10.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6920382 + ... + 6922018.

Almost surely, 211330004400 is an apocalyptic number.

11330004400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11330004400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16131561264).

11330004400 is an abundant number, since it is smaller than the sum of its proper divisors (20933118128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11330004400 is a wasteful number, since it uses less digits than its factorization.

11330004400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1701 (or 1668 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 11330004400 its reverse (440003311), we get a palindrome (11770007711).

The spelling of 11330004400 in words is "eleven billion, three hundred thirty million, four thousand, four hundred".