Search a number
-
+
11330020021 = 89779126199
BaseRepresentation
bin10101000110101001…
…00110001010110101
31002020121102122121011
422203110212022311
5141200441120041
65112133352221
7550524403225
oct124324461265
932217378534
1011330020021
114894556811
122242498671
1310b7406578
14796a5a085
15464a2ce81
hex2a35262b5

11330020021 has 4 divisors (see below), whose sum is σ = 11330236000. Its totient is φ = 11329804044.

The previous prime is 11330020007. The next prime is 11330020057. The reversal of 11330020021 is 12002003311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11330020021 - 27 = 11330019893 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11330019983 and 11330020010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11330020061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26680 + ... + 152878.

It is an arithmetic number, because the mean of its divisors is an integer number (2832559000).

Almost surely, 211330020021 is an apocalyptic number.

It is an amenable number.

11330020021 is a deficient number, since it is larger than the sum of its proper divisors (215979).

11330020021 is an equidigital number, since it uses as much as digits as its factorization.

11330020021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215978.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 11330020021 its reverse (12002003311), we get a palindrome (23332023332).

The spelling of 11330020021 in words is "eleven billion, three hundred thirty million, twenty thousand, twenty-one".

Divisors: 1 89779 126199 11330020021