Base | Representation |
---|---|
bin | 11001110000101111000010… |
… | …111001011010000011010011 |
3 | 112212011101122120220101222002 |
4 | 121300233002321122003103 |
5 | 104322302313301130003 |
6 | 1040545222055104215 |
7 | 32602445610004163 |
oct | 3160570271320323 |
9 | 485141576811862 |
10 | 113300212130003 |
11 | 33112394020618 |
12 | 1085a40b97206b |
13 | 4b2b219873472 |
14 | 1dd9a8c1d85a3 |
15 | d172ea068a88 |
hex | 670bc2e5a0d3 |
113300212130003 has 4 divisors (see below), whose sum is σ = 114852269830488. Its totient is φ = 111748154429520.
The previous prime is 113300212129999. The next prime is 113300212130029. The reversal of 113300212130003 is 300031212003311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113300212130003 - 22 = 113300212129999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113300212130093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 776028850133 + ... + 776028850278.
It is an arithmetic number, because the mean of its divisors is an integer number (28713067457622).
Almost surely, 2113300212130003 is an apocalyptic number.
113300212130003 is a deficient number, since it is larger than the sum of its proper divisors (1552057700485).
113300212130003 is an equidigital number, since it uses as much as digits as its factorization.
113300212130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1552057700484.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 113300212130003 its reverse (300031212003311), we get a palindrome (413331424133314).
The spelling of 113300212130003 in words is "one hundred thirteen trillion, three hundred billion, two hundred twelve million, one hundred thirty thousand, three".
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