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11330031200003 = 109103945240367
BaseRepresentation
bin1010010011011111101001…
…1111000010011100000011
31111010010210100120201210022
42210313322133002130003
52441112400441400003
640032540001324055
72246365510121645
oct244677237023403
944103710521708
1011330031200003
11367904826a26a
12132ba0463662b
13642556c1cc99
142b253ad24895
15149ac05a6738
hexa4dfa7c2703

11330031200003 has 4 divisors (see below), whose sum is σ = 11433976440480. Its totient is φ = 11226085959528.

The previous prime is 11330031199967. The next prime is 11330031200011. The reversal of 11330031200003 is 30000213003311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11330031200003 - 210 = 11330031198979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11330031200063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51972620075 + ... + 51972620292.

It is an arithmetic number, because the mean of its divisors is an integer number (2858494110120).

Almost surely, 211330031200003 is an apocalyptic number.

11330031200003 is a deficient number, since it is larger than the sum of its proper divisors (103945240477).

11330031200003 is a wasteful number, since it uses less digits than its factorization.

11330031200003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103945240476.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 11330031200003 its reverse (30000213003311), we get a palindrome (41330244203314).

The spelling of 11330031200003 in words is "eleven trillion, three hundred thirty billion, thirty-one million, two hundred thousand, three".

Divisors: 1 109 103945240367 11330031200003