Base | Representation |
---|---|
bin | 1010010011011111111111… |
… | …1110011010100000010001 |
3 | 1111010011000202220110111012 |
4 | 2210313333332122200101 |
5 | 2441113043031423441 |
6 | 40032553051500305 |
7 | 2246401006056326 |
oct | 244677776324021 |
9 | 44104022813435 |
10 | 11330123311121 |
11 | 367909526275a |
12 | 132ba2b457695 |
13 | 642570030ac4 |
14 | 2b2549260b4d |
15 | 149ac86ed9eb |
hex | a4dfff9a811 |
11330123311121 has 2 divisors, whose sum is σ = 11330123311122. Its totient is φ = 11330123311120.
The previous prime is 11330123311109. The next prime is 11330123311139. The reversal of 11330123311121 is 12111332103311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11316361440400 + 13761870721 = 3363980^2 + 117311^2 .
It is a cyclic number.
It is not a de Polignac number, because 11330123311121 - 210 = 11330123310097 is a prime.
It is not a weakly prime, because it can be changed into another prime (11330123311141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665061655560 + 5665061655561.
It is an arithmetic number, because the mean of its divisors is an integer number (5665061655561).
Almost surely, 211330123311121 is an apocalyptic number.
It is an amenable number.
11330123311121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330123311121 is an equidigital number, since it uses as much as digits as its factorization.
11330123311121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 11330123311121 its reverse (12111332103311), we get a palindrome (23441455414432).
The spelling of 11330123311121 in words is "eleven trillion, three hundred thirty billion, one hundred twenty-three million, three hundred eleven thousand, one hundred twenty-one".
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