Base | Representation |
---|---|
bin | 1010010011011111111111… |
… | …1110011010100001001111 |
3 | 1111010011000202220110120111 |
4 | 2210313333332122201033 |
5 | 2441113043031424213 |
6 | 40032553051500451 |
7 | 2246401006056445 |
oct | 244677776324117 |
9 | 44104022813514 |
10 | 11330123311183 |
11 | 3679095262806 |
12 | 132ba2b457727 |
13 | 642570030b41 |
14 | 2b2549260b95 |
15 | 149ac86eda3d |
hex | a4dfff9a84f |
11330123311183 has 2 divisors, whose sum is σ = 11330123311184. Its totient is φ = 11330123311182.
The previous prime is 11330123311181. The next prime is 11330123311189. The reversal of 11330123311183 is 38111332103311.
It is a weak prime.
It is an emirp because it is prime and its reverse (38111332103311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11330123311183 - 21 = 11330123311181 is a prime.
It is a super-2 number, since 2×113301233111832 (a number of 27 digits) contains 22 as substring.
Together with 11330123311181, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11330123311181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665061655591 + 5665061655592.
It is an arithmetic number, because the mean of its divisors is an integer number (5665061655592).
Almost surely, 211330123311183 is an apocalyptic number.
11330123311183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330123311183 is an equidigital number, since it uses as much as digits as its factorization.
11330123311183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
Adding to 11330123311183 its reverse (38111332103311), we get a palindrome (49441455414494).
The spelling of 11330123311183 in words is "eleven trillion, three hundred thirty billion, one hundred twenty-three million, three hundred eleven thousand, one hundred eighty-three".
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