Base | Representation |
---|---|
bin | 110100110000101001… |
… | …0001010001110001111 |
3 | 101211110011101101202120 |
4 | 1221201102022032033 |
5 | 3324020113100421 |
6 | 124014440024023 |
7 | 11120466106056 |
oct | 1514122121617 |
9 | 354404341676 |
10 | 113301300111 |
11 | 440616a280a |
12 | 19b60462013 |
13 | a8b8445c1c |
14 | 56ab81b39d |
15 | 2e31d558c6 |
hex | 1a6148a38f |
113301300111 has 4 divisors (see below), whose sum is σ = 151068400152. Its totient is φ = 75534200072.
The previous prime is 113301300041. The next prime is 113301300191. The reversal of 113301300111 is 111003103311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113301300111 - 210 = 113301299087 is a prime.
It is a super-2 number, since 2×1133013001112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113301300191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18883550016 + ... + 18883550021.
It is an arithmetic number, because the mean of its divisors is an integer number (37767100038).
Almost surely, 2113301300111 is an apocalyptic number.
113301300111 is a deficient number, since it is larger than the sum of its proper divisors (37767100041).
113301300111 is an equidigital number, since it uses as much as digits as its factorization.
113301300111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37767100040.
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 113301300111 its reverse (111003103311), we get a palindrome (224304403422).
The spelling of 113301300111 in words is "one hundred thirteen billion, three hundred one million, three hundred thousand, one hundred eleven".
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