Base | Representation |
---|---|
bin | 1010010011100000101110… |
… | …1101001110100000100011 |
3 | 1111010011112111021000011020 |
4 | 2210320023231032200203 |
5 | 2441113443423212011 |
6 | 40033024402220523 |
7 | 2246405616033450 |
oct | 244701355164043 |
9 | 44104474230136 |
10 | 11330320132131 |
11 | 3679186374250 |
12 | 132ba85354743 |
13 | 6425a1a44140 |
14 | 2b2567456827 |
15 | 149adab2b006 |
hex | a4e0bb4e823 |
11330320132131 has 64 divisors (see below), whose sum is σ = 20324301312000. Its totient is φ = 5422231808640.
The previous prime is 11330320132121. The next prime is 11330320132139. The reversal of 11330320132131 is 13123102303311.
It is not a de Polignac number, because 11330320132131 - 25 = 11330320132099 is a prime.
It is a super-2 number, since 2×113303201321312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11330320132139) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2282065 + ... + 5279058.
It is an arithmetic number, because the mean of its divisors is an integer number (317567208000).
Almost surely, 211330320132131 is an apocalyptic number.
11330320132131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11330320132131 is a deficient number, since it is larger than the sum of its proper divisors (8993981179869).
11330320132131 is a wasteful number, since it uses less digits than its factorization.
11330320132131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7561656.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11330320132131 its reverse (13123102303311), we get a palindrome (24453422435442).
The spelling of 11330320132131 in words is "eleven trillion, three hundred thirty billion, three hundred twenty million, one hundred thirty-two thousand, one hundred thirty-one".
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