1133033220133 has 4 divisors (see below), whose sum is σ = 1199682233100. Its totient is φ = 1066384207168.

The previous prime is 1133033220127. The next prime is 1133033220139. The reversal of 1133033220133 is 3310223303311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1133033220127) and next prime (1133033220139).

It can be written as a sum of positive squares in 2 ways, for example, as 919262923524 + 213770296609 = 958782^2 + 462353^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133033220133 - 2⁵ = 1133033220101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133033220098 and 1133033220107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133033220139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33324506458 + ... + 33324506491.

It is an arithmetic number, because the mean of its divisors is an integer number (299920558275).

Almost surely, 2^{1133033220133} is an apocalyptic number.

It is an amenable number.

1133033220133 is a deficient number, since it is larger than the sum of its proper divisors (66649012967).

1133033220133 is an equidigital number, since it uses as much as digits as its factorization.

1133033220133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66649012966.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 1133033220133 its reverse (3310223303311), we get a palindrome (4443256523444).

The spelling of 1133033220133 in words is "one trillion, one hundred thirty-three billion, thirty-three million, two hundred twenty thousand, one hundred thirty-three".