Base | Representation |
---|---|
bin | 10101000110101100… |
… | …00110001001001101 |
3 | 1002020122011121211212 |
4 | 22203112012021031 |
5 | 141201041210013 |
6 | 5112150024205 |
7 | 550530631304 |
oct | 124326061115 |
9 | 32218147755 |
10 | 11330413133 |
11 | 48947a50a6 |
12 | 2242648065 |
13 | 10b7513490 |
14 | 796b1d43b |
15 | 464aa96a8 |
hex | 2a358624d |
11330413133 has 16 divisors (see below), whose sum is σ = 12328942080. Its totient is φ = 10350163584.
The previous prime is 11330413123. The next prime is 11330413153. The reversal of 11330413133 is 33131403311.
It is a cyclic number.
It is not a de Polignac number, because 11330413133 - 24 = 11330413117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11330413099 and 11330413108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11330413103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3631148 + ... + 3634266.
It is an arithmetic number, because the mean of its divisors is an integer number (770558880).
Almost surely, 211330413133 is an apocalyptic number.
11330413133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11330413133 is a deficient number, since it is larger than the sum of its proper divisors (998528947).
11330413133 is a wasteful number, since it uses less digits than its factorization.
11330413133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5948.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 11330413133 its reverse (33131403311), we get a palindrome (44461816444).
The spelling of 11330413133 in words is "eleven billion, three hundred thirty million, four hundred thirteen thousand, one hundred thirty-three".
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