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11330413242453 = 321942164823377
BaseRepresentation
bin1010010011100001000101…
…0000011010100001010101
31111010011202222110111111200
42210320101100122201111
52441114141242224303
640033041530023113
72246411126332224
oct244702120324125
944104688414450
1011330413242453
11367922398a428
12132bab0577a99
136425b81149c6
142b2575972cbb
15149ae3dbe3a3
hexa4e1141a855

11330413242453 has 12 divisors (see below), whose sum is σ = 16366995417708. Its totient is φ = 7553219771520.

The previous prime is 11330413242437. The next prime is 11330413242479. The reversal of 11330413242453 is 35424231403311.

11330413242453 is a `hidden beast` number, since 1 + 1 + 3 + 30 + 4 + 132 + 42 + 453 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 9897360044049 + 1433053198404 = 3146007^2 + 1197102^2 .

It is not a de Polignac number, because 11330413242453 - 24 = 11330413242437 is a prime.

It is a super-2 number, since 2×113304132424532 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11330413242053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 32236900 + ... + 32586477.

It is an arithmetic number, because the mean of its divisors is an integer number (1363916284809).

Almost surely, 211330413242453 is an apocalyptic number.

It is an amenable number.

11330413242453 is a deficient number, since it is larger than the sum of its proper divisors (5036582175255).

11330413242453 is a wasteful number, since it uses less digits than its factorization.

11330413242453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64842804 (or 64842801 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 36.

Adding to 11330413242453 its reverse (35424231403311), we get a palindrome (46754644645764).

The spelling of 11330413242453 in words is "eleven trillion, three hundred thirty billion, four hundred thirteen million, two hundred forty-two thousand, four hundred fifty-three".

Divisors: 1 3 9 19421 58263 174789 64823377 194470131 583410393 1258934804717 3776804414151 11330413242453