Base | Representation |
---|---|
bin | 10101000110101100… |
… | …00110011000111111 |
3 | 1002020122011200020021 |
4 | 22203112012120333 |
5 | 141201041223033 |
6 | 5112150033011 |
7 | 550530634246 |
oct | 124326063077 |
9 | 32218150207 |
10 | 11330414143 |
11 | 48947a5934 |
12 | 2242648767 |
13 | 10b7513a89 |
14 | 796b1d95d |
15 | 464aa9b2d |
hex | 2a358663f |
11330414143 has 2 divisors, whose sum is σ = 11330414144. Its totient is φ = 11330414142.
The previous prime is 11330414131. The next prime is 11330414149. The reversal of 11330414143 is 34141403311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11330414143 - 217 = 11330283071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11330414149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665207071 + 5665207072.
It is an arithmetic number, because the mean of its divisors is an integer number (5665207072).
Almost surely, 211330414143 is an apocalyptic number.
11330414143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330414143 is an equidigital number, since it uses as much as digits as its factorization.
11330414143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11330414143 its reverse (34141403311), we get a palindrome (45471817454).
The spelling of 11330414143 in words is "eleven billion, three hundred thirty million, four hundred fourteen thousand, one hundred forty-three".
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