11331003112133 has 4 divisors (see below), whose sum is σ = 11349308448960. Its totient is φ = 11312697775308.

The previous prime is 11331003112111. The next prime is 11331003112141. The reversal of 11331003112133 is 33121130013311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331003112133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331003112099 and 11331003112108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331003112103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9152667485 + ... + 9152668722.

It is an arithmetic number, because the mean of its divisors is an integer number (2837327112240).

Almost surely, 2^{11331003112133} is an apocalyptic number.

It is an amenable number.

11331003112133 is a deficient number, since it is larger than the sum of its proper divisors (18305336827).

11331003112133 is an equidigital number, since it uses as much as digits as its factorization.

11331003112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18305336826.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331003112133 its reverse (33121130013311), we get a palindrome (44452133125444).

The spelling of 11331003112133 in words is "eleven trillion, three hundred thirty-one billion, three million, one hundred twelve thousand, one hundred thirty-three".