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1133101320000 = 26354133767293
BaseRepresentation
bin10000011111010010000…
…110100000011101000000
311000022201210001001100120
4100133102012200131000
5122031042414220000
62224312313420240
7144602210206446
oct20372206403500
94008653031316
101133101320000
113a7600178701
1216372940a680
1382b0a83b160
143cbb1770b96
151e71b9d46a0
hex107d21a0740

1133101320000 has 1120 divisors, whose sum is σ = 4219710160512. Its totient is φ = 266416128000.

The previous prime is 1133101319983. The next prime is 1133101320011. The reversal of 1133101320000 is 231013311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 3867239854 + ... + 3867240146.

Almost surely, 21133101320000 is an apocalyptic number.

1133101320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1133101320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2109855080256).

1133101320000 is an abundant number, since it is smaller than the sum of its proper divisors (3086608840512).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133101320000 is a wasteful number, since it uses less digits than its factorization.

1133101320000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 445 (or 420 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1133101320000 its reverse (231013311), we get a palindrome (1133332333311).

The spelling of 1133101320000 in words is "one trillion, one hundred thirty-three billion, one hundred one million, three hundred twenty thousand".