Base | Representation |
---|---|
bin | 1010010011100011010110… |
… | …0110011101001010111011 |
3 | 1111010020100110211101221211 |
4 | 2210320311212131022323 |
5 | 2441121413342002001 |
6 | 40033222231143551 |
7 | 2246432212231603 |
oct | 244706546351273 |
9 | 44106313741854 |
10 | 11331023000251 |
11 | 36795070a2499 |
12 | 1330040814bb7 |
13 | 642684548b36 |
14 | 2b25d2939c03 |
15 | 149b2c6b8351 |
hex | a4e3599d2bb |
11331023000251 has 2 divisors, whose sum is σ = 11331023000252. Its totient is φ = 11331023000250.
The previous prime is 11331023000249. The next prime is 11331023000293. The reversal of 11331023000251 is 15200032013311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331023000251 - 21 = 11331023000249 is a prime.
Together with 11331023000249, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11331023000351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511500125 + 5665511500126.
It is an arithmetic number, because the mean of its divisors is an integer number (5665511500126).
Almost surely, 211331023000251 is an apocalyptic number.
11331023000251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331023000251 is an equidigital number, since it uses as much as digits as its factorization.
11331023000251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 11331023000251 its reverse (15200032013311), we get a palindrome (26531055013562).
The spelling of 11331023000251 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, two hundred fifty-one", and thus it is an aban number.
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