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11331023000351 is a prime number
BaseRepresentation
bin1010010011100011010110…
…0110011101001100011111
31111010020100110211102002112
42210320311212131030133
52441121413342002401
640033222231144235
72246432212232105
oct244706546351437
944106313742075
1011331023000351
1136795070a257a
12133004081507b
13642684548bb2
142b25d2939c75
15149b2c6b83bb
hexa4e3599d31f

11331023000351 has 2 divisors, whose sum is σ = 11331023000352. Its totient is φ = 11331023000350.

The previous prime is 11331023000333. The next prime is 11331023000369. The reversal of 11331023000351 is 15300032013311.

It is a balanced prime because it is at equal distance from previous prime (11331023000333) and next prime (11331023000369).

It is a cyclic number.

It is not a de Polignac number, because 11331023000351 - 210 = 11331022999327 is a prime.

It is a super-2 number, since 2×113310230003512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331023000251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511500175 + 5665511500176.

It is an arithmetic number, because the mean of its divisors is an integer number (5665511500176).

Almost surely, 211331023000351 is an apocalyptic number.

11331023000351 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331023000351 is an equidigital number, since it uses as much as digits as its factorization.

11331023000351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 11331023000351 its reverse (15300032013311), we get a palindrome (26631055013662).

The spelling of 11331023000351 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, three hundred fifty-one", and thus it is an aban number.