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1133102301300 = 2234522415631031
BaseRepresentation
bin10000011111010010001…
…010010000000001110100
311000022201211212220110000
4100133102022100001310
5122031043142120200
62224312350431300
7144602221434414
oct20372212200164
94008654786400
101133102301300
113a76007889a2
12163729802530
1382b0aac29c8
143cbb1948644
151e71bb2a300
hex107d2290074

1133102301300 has 360 divisors, whose sum is σ = 3698445909312. Its totient is φ = 300081024000.

The previous prime is 1133102301293. The next prime is 1133102301301. The reversal of 1133102301300 is 31032013311.

It is a happy number.

1133102301300 is a `hidden beast` number, since 1 + 1 + 331 + 0 + 2 + 30 + 1 + 300 = 666.

It is a super-2 number, since 2×11331023013002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133102301301) by changing a digit.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 1099031785 + ... + 1099032815.

Almost surely, 21133102301300 is an apocalyptic number.

1133102301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1133102301300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1849222954656).

1133102301300 is an abundant number, since it is smaller than the sum of its proper divisors (2565343608012).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133102301300 is a wasteful number, since it uses less digits than its factorization.

1133102301300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1861 (or 1845 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 1133102301300 its reverse (31032013311), we get a palindrome (1164134314611).

The spelling of 1133102301300 in words is "one trillion, one hundred thirty-three billion, one hundred two million, three hundred one thousand, three hundred".