Base | Representation |
---|---|
bin | 1010010011100011010110… |
… | …0110111000110001010111 |
3 | 1111010020100111001011000221 |
4 | 2210320311212320301113 |
5 | 2441121413404111203 |
6 | 40033222233415211 |
7 | 2246432213212315 |
oct | 244706546706127 |
9 | 44106314034027 |
10 | 11331023113303 |
11 | 367950716a423 |
12 | 133004086a507 |
13 | 64268458842a |
14 | 2b25d29690b5 |
15 | 149b2c6dbabd |
hex | a4e359b8c57 |
11331023113303 has 2 divisors, whose sum is σ = 11331023113304. Its totient is φ = 11331023113302.
The previous prime is 11331023113271. The next prime is 11331023113309. The reversal of 11331023113303 is 30331132013311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331023113303 - 25 = 11331023113271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331023113309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511556651 + 5665511556652.
It is an arithmetic number, because the mean of its divisors is an integer number (5665511556652).
Almost surely, 211331023113303 is an apocalyptic number.
11331023113303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331023113303 is an equidigital number, since it uses as much as digits as its factorization.
11331023113303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 11331023113303 its reverse (30331132013311), we get a palindrome (41662155126614).
The spelling of 11331023113303 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, one hundred thirteen thousand, three hundred three".
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