Base | Representation |
---|---|
bin | 10101000110110001… |
… | …01110101011000111 |
3 | 1002020200110200202110 |
4 | 22203120232223013 |
5 | 141201230302211 |
6 | 5112212512103 |
7 | 550536534654 |
oct | 124330565307 |
9 | 32220420673 |
10 | 11331103431 |
11 | 489512679a |
12 | 224291b633 |
13 | 10b76c573b |
14 | 796c5cc2b |
15 | 464b93ea6 |
hex | 2a362eac7 |
11331103431 has 24 divisors (see below), whose sum is σ = 15342735744. Its totient is φ = 7438519920.
The previous prime is 11331103423. The next prime is 11331103447. The reversal of 11331103431 is 13430113311.
It is not a de Polignac number, because 11331103431 - 23 = 11331103423 is a prime.
It is a super-2 number, since 2×113311034312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331103398 and 11331103407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331103481) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10989886 + ... + 10990916.
It is an arithmetic number, because the mean of its divisors is an integer number (639280656).
Almost surely, 211331103431 is an apocalyptic number.
11331103431 is a deficient number, since it is larger than the sum of its proper divisors (4011632313).
11331103431 is an equidigital number, since it uses as much as digits as its factorization.
11331103431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1779 (or 1700 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11331103431 its reverse (13430113311), we get a palindrome (24761216742).
The spelling of 11331103431 in words is "eleven billion, three hundred thirty-one million, one hundred three thousand, four hundred thirty-one".
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