11331120010031 has 2 divisors, whose sum is σ = 11331120010032. Its totient is φ = 11331120010030.

The previous prime is 11331120009983. The next prime is 11331120010099. The reversal of 11331120010031 is 13001002113311.

11331120010031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331120010031 is a prime.

It is a super-2 number, since 2×11331120010031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331120009991 and 11331120010009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331120010631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560005015 + 5665560005016.

It is an arithmetic number, because the mean of its divisors is an integer number (5665560005016).

Almost surely, 2^{11331120010031} is an apocalyptic number.

11331120010031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331120010031 is an equidigital number, since it uses as much as digits as its factorization.

11331120010031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11331120010031 its reverse (13001002113311), we get a palindrome (24332122123342).

The spelling of 11331120010031 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty million, ten thousand, thirty-one".