Base | Representation |
---|---|
bin | 10101000110110001… |
… | …10010111111101010 |
3 | 1002020200111121000222 |
4 | 22203120302333222 |
5 | 141201231334010 |
6 | 5112213130042 |
7 | 550536640400 |
oct | 124330627752 |
9 | 32220447028 |
10 | 11331121130 |
11 | 489513901a |
12 | 2242929922 |
13 | 10b7700804 |
14 | 796c65470 |
15 | 464b99355 |
hex | 2a3632fea |
11331121130 has 48 divisors (see below), whose sum is σ = 23863303080. Its totient is φ = 3862470528.
The previous prime is 11331121121. The next prime is 11331121141. The reversal of 11331121130 is 3112113311.
It can be written as a sum of positive squares in 4 ways, for example, as 7689360721 + 3641760409 = 87689^2 + 60347^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11331121099 and 11331121108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17936 + ... + 151604.
Almost surely, 211331121130 is an apocalyptic number.
11331121130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11331121130 is an abundant number, since it is smaller than the sum of its proper divisors (12532181950).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331121130 is a wasteful number, since it uses less digits than its factorization.
11331121130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133863 (or 133856 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11331121130 its reverse (3112113311), we get a palindrome (14443234441).
The spelling of 11331121130 in words is "eleven billion, three hundred thirty-one million, one hundred twenty-one thousand, one hundred thirty".
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