Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000111111001101010111 |
3 | 1111010020121101112210201112 |
4 | 2210320323200333031113 |
5 | 2441122114242330403 |
6 | 40033240134045235 |
7 | 2246434525535504 |
oct | 244707340771527 |
9 | 44106541483645 |
10 | 11331122230103 |
11 | 3679558108335 |
12 | 1330069aa981b |
13 | 64269bc7cc20 |
14 | 2b2601baa4ab |
15 | 149b362699d8 |
hex | a4e3b83f357 |
11331122230103 has 16 divisors (see below), whose sum is σ = 12350546388096. Its totient is φ = 10332828154080.
The previous prime is 11331122230079. The next prime is 11331122230159. The reversal of 11331122230103 is 30103222113311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331122230103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331122230193) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17229308 + ... + 17874878.
It is an arithmetic number, because the mean of its divisors is an integer number (771909149256).
Almost surely, 211331122230103 is an apocalyptic number.
11331122230103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11331122230103 is a deficient number, since it is larger than the sum of its proper divisors (1019424157993).
11331122230103 is a wasteful number, since it uses less digits than its factorization.
11331122230103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 661934.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11331122230103 its reverse (30103222113311), we get a palindrome (41434344343414).
The spelling of 11331122230103 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, two hundred thirty thousand, one hundred three".
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