Search a number
-
+
11331123000161 is a prime number
BaseRepresentation
bin1010010011100011101110…
…0011111011001101100001
31111010020121102222221001012
42210320323203323031201
52441122114442001121
640033240202350305
72246434535223536
oct244707343731541
944106542887035
1011331123000161
113679558593948
12133006a1bb395
1364269c18c593
142b2601d2ad8d
15149b3636cc5b
hexa4e3b8fb361

11331123000161 has 2 divisors, whose sum is σ = 11331123000162. Its totient is φ = 11331123000160.

The previous prime is 11331123000023. The next prime is 11331123000187. The reversal of 11331123000161 is 16100032113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8994336891136 + 2336786109025 = 2999056^2 + 1528655^2 .

It is an emirp because it is prime and its reverse (16100032113311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331123000161 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331123000661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561500080 + 5665561500081.

It is an arithmetic number, because the mean of its divisors is an integer number (5665561500081).

Almost surely, 211331123000161 is an apocalyptic number.

It is an amenable number.

11331123000161 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331123000161 is an equidigital number, since it uses as much as digits as its factorization.

11331123000161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 11331123000161 its reverse (16100032113311), we get a palindrome (27431155113472).

The spelling of 11331123000161 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-three million, one hundred sixty-one", and thus it is an aban number.