Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0100011000011101001111 |
3 | 1111010020121110020000100212 |
4 | 2210320323210120131033 |
5 | 2441122120004314301 |
6 | 40033240205113035 |
7 | 2246434536233015 |
oct | 244707344303517 |
9 | 44106543200325 |
10 | 11331123119951 |
11 | 3679558665948 |
12 | 133006a25877b |
13 | 64269c201c6b |
14 | 2b2601d5c8b5 |
15 | 149b363934bb |
hex | a4e3b91874f |
11331123119951 has 2 divisors, whose sum is σ = 11331123119952. Its totient is φ = 11331123119950.
The previous prime is 11331123119947. The next prime is 11331123120017. The reversal of 11331123119951 is 15991132113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331123119951 - 22 = 11331123119947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331123119899 and 11331123119908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331123119051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561559975 + 5665561559976.
It is an arithmetic number, because the mean of its divisors is an integer number (5665561559976).
Almost surely, 211331123119951 is an apocalyptic number.
11331123119951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331123119951 is an equidigital number, since it uses as much as digits as its factorization.
11331123119951 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21870, while the sum is 41.
The spelling of 11331123119951 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-three million, one hundred nineteen thousand, nine hundred fifty-one".
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