Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1111001000011010011001 |
3 | 1111010020121221102021020212 |
4 | 2210320323333020122121 |
5 | 2441122123303211441 |
6 | 40033241015300505 |
7 | 2246434652646452 |
oct | 244707377103231 |
9 | 44106557367225 |
10 | 11331130132121 |
11 | 3679561615228 |
12 | 133007067a735 |
13 | 6426a07b8887 |
14 | 2b2602c66129 |
15 | 149b36ccaeeb |
hex | a4e3bfc8699 |
11331130132121 has 2 divisors, whose sum is σ = 11331130132122. Its totient is φ = 11331130132120.
The previous prime is 11331130132079. The next prime is 11331130132129. The reversal of 11331130132121 is 12123103113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8104925017225 + 3226205114896 = 2846915^2 + 1796164^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331130132121 - 242 = 6933083621017 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331130132129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565066060 + 5665565066061.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565066061).
Almost surely, 211331130132121 is an apocalyptic number.
It is an amenable number.
11331130132121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130132121 is an equidigital number, since it uses as much as digits as its factorization.
11331130132121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 11331130132121 its reverse (12123103113311), we get a palindrome (23454233245432).
The spelling of 11331130132121 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, one hundred thirty-two thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •