11331130212371 has 2 divisors, whose sum is σ = 11331130212372. Its totient is φ = 11331130212370.

The previous prime is 11331130212317. The next prime is 11331130212397. The reversal of 11331130212371 is 17321203113311.

Together with previous prime (11331130212317) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331130212371 is a prime.

It is a super-2 number, since 2×11331130212371² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331130212301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565106185 + 5665565106186.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565106186).

Almost surely, 2^{11331130212371} is an apocalyptic number.

11331130212371 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331130212371 is an equidigital number, since it uses as much as digits as its factorization.

11331130212371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 29.

Adding to 11331130212371 its reverse (17321203113311), we get a palindrome (28652333325682).

The spelling of 11331130212371 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, two hundred twelve thousand, three hundred seventy-one".