Search a number
-
+
11331130212397 is a prime number
BaseRepresentation
bin1010010011100011101111…
…1111011100000000101101
31111010020121221120100101001
42210320323333130000231
52441122123313244042
640033241021120301
72246434653432502
oct244707377340055
944106557510331
1011331130212397
11367956166a576
1213300706b9091
136426a0816288
142b2602c874a9
15149b36ce4bb7
hexa4e3bfdc02d

11331130212397 has 2 divisors, whose sum is σ = 11331130212398. Its totient is φ = 11331130212396.

The previous prime is 11331130212371. The next prime is 11331130212469. The reversal of 11331130212397 is 79321203113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10947753770121 + 383376442276 = 3308739^2 + 619174^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331130212397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331130212317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565106198 + 5665565106199.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565106199).

Almost surely, 211331130212397 is an apocalyptic number.

It is an amenable number.

11331130212397 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331130212397 is an equidigital number, since it uses as much as digits as its factorization.

11331130212397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 37.

The spelling of 11331130212397 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, two hundred twelve thousand, three hundred ninety-seven".