Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010100011110111101111 |
3 | 1111010020122000002221022112 |
4 | 2210320330002203313233 |
5 | 2441122124020443043 |
6 | 40033241050434235 |
7 | 2246434663412246 |
oct | 244707402436757 |
9 | 44106560087275 |
10 | 11331131031023 |
11 | 3679562079621 |
12 | 1330070a3297b |
13 | 6426a0a41a7b |
14 | 2b260301b95d |
15 | 149b36e07518 |
hex | a4e3c0a3def |
11331131031023 has 2 divisors, whose sum is σ = 11331131031024. Its totient is φ = 11331131031022.
The previous prime is 11331131030981. The next prime is 11331131031029. The reversal of 11331131031023 is 32013013113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331131031023 - 214 = 11331131014639 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11331131031023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331131031029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565515511 + 5665565515512.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565515512).
Almost surely, 211331131031023 is an apocalyptic number.
11331131031023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131031023 is an equidigital number, since it uses as much as digits as its factorization.
11331131031023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11331131031023 its reverse (32013013113311), we get a palindrome (43344144144334).
The spelling of 11331131031023 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, thirty-one thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •